What is x^2-6x-7>= 4 ?

The solution to x^2-6x-7>= 4 is x = 2sqrt(5)+3

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x^2-6x-7>= 4

x^{2} - 6 x - 7 \geq 4

x \leq - 25 + 3 or x \geq 25 + 3

Interval Notation

(- \infty, - 25 + 3] \cup [25 + 3, \infty)

Decimal Notation

x \leq - 1.47213 \dots or x \geq 7.47213 \dots

Solution steps

x^{2} - 6 x - 7 \geq 4

Rewrite in standard form

x^{2} - 6 x - 11 \geq 0

Complete the square

x^{2} - 6 x - 11 : (x - 3)^{2} - 20

(x - 3)^{2} - 20 \geq 0

Move

20

to the right side

(x - 3)^{2} \geq 20

For

u^{n} \geq a

, if

n

is even then

x - 3 \leq - 20 or x - 3 \geq 20

x - 3 \leq - 20 : x \leq - 25 + 3

x - 3 \geq 20 : x \geq 25 + 3

Combine the intervals

x \leq - 25 + 3 or x \geq 25 + 3

6 x^{2} - 12 x = - 3

4 m^{2} - 20 am

\frac{( 2 π ( 149.6 \cdot 1 0 ^{6} ) )}{1}

6 x^{2} + 96 x - 13 = - 13

(- \frac{5}{8}) \cdot (\frac{2}{3})

What is x^2-6x-7>= 4 ?
The solution to x^2-6x-7>= 4 is x<=-2sqrt(5)+3\lor x>= 2sqrt(5)+3