What are the solutions to the equation 2x^2-9x+9=0 ?

The solutions to the equation 2x^2-9x+9=0 are x=3,x= 3/2

Find the zeros of 2x^2-9x+9=0

The zeros of 2x^2-9x+9=0 are x=3,x= 3/2

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2 x^{2} - 9 x + 9 = 0

x = 3, x = \frac{3}{2}

Decimal Notation

x = 3, x = 1.5

Solution steps

2 x^{2} - 9 x + 9 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 9 ) \pm ( - 9 ) ^{2} - 4 \cdot 2 \cdot 9}{2 \cdot 2}

(- 9)^{2} - 4 \cdot 2 \cdot 9 = 3

x_{1, 2} = \frac{- ( - 9 ) \pm 3}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- ( - 9 ) + 3}{2 \cdot 2}, x_{2} = \frac{- ( - 9 ) - 3}{2 \cdot 2}

x = \frac{- ( - 9 ) + 3}{2 \cdot 2} : 3

x = \frac{- ( - 9 ) - 3}{2 \cdot 2} : \frac{3}{2}

The solutions to the quadratic equation are:

x = 3, x = \frac{3}{2}

4 x^{2} + 80 = 0

21 b - 15 a

\frac{n + 1}{2 n - 1} \leq \frac{n + 2}{2 n + 1}

4 x^{2} + 44 x + 121

\frac{( x ^{a + b} ) ^{2} ( y ^{a + b} ) ^{2}}{( x y ) ^{2 a - b}}

What are the solutions to the equation 2x^2-9x+9=0 ?
The solutions to the equation 2x^2-9x+9=0 are x=3,x= 3/2
Find the zeros of 2x^2-9x+9=0
The zeros of 2x^2-9x+9=0 are x=3,x= 3/2