What are the solutions to the equation 4x^2+80=0 ?

The solutions to the equation 4x^2+80=0 are x=2sqrt(5)i,x=-2sqrt(5)i

Find the zeros of 4x^2+80=0

The zeros of 4x^2+80=0 are x=2sqrt(5)i,x=-2sqrt(5)i

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4 x^{2} + 80 = 0

x = 25 i, x = - 25 i

Solution steps

4 x^{2} + 80 = 0

Move

80

to the right side

4 x^{2} = - 80

Divide both sides by

4

x^{2} = - 20

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = - 20, x = - - 20

- 20 = 25 i

- - 20 = - 25 i

x = 25 i, x = - 25 i

21 b - 15 a

\frac{n + 1}{2 n - 1} \leq \frac{n + 2}{2 n + 1}

4 x^{2} + 44 x + 121

\frac{( x ^{a + b} ) ^{2} ( y ^{a + b} ) ^{2}}{( x y ) ^{2 a - b}}

25 x^{2} - y^{2} + 4 y - 4

What are the solutions to the equation 4x^2+80=0 ?
The solutions to the equation 4x^2+80=0 are x=2sqrt(5)i,x=-2sqrt(5)i
Find the zeros of 4x^2+80=0
The zeros of 4x^2+80=0 are x=2sqrt(5)i,x=-2sqrt(5)i