What is simplify-ln(n+1)+ln(n-1) ?

The solution to simplify-ln(n+1)+ln(n-1) is ln((n-1)/(n+1))

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simplify-ln(n+1)+ln(n-1)

simplify

- ln (n + 1) + ln (n - 1)

ln (\frac{n - 1}{n + 1})

Solution steps

- ln (n + 1) + ln (n - 1)

Apply log rule:

lo g_{c} (a) - lo g_{c} (b) = lo g_{c} (\frac{a}{b})

ln (n - 1) - ln (n + 1) = ln (\frac{n - 1}{n + 1})

= ln (\frac{n - 1}{n + 1})

\frac{1}{2} ln (\frac{∣ x - 1 ∣}{∣ x + 1 ∣}) + C

ln (\frac{x + 13}{( x - 4 ) ^{3} 2 x + 1})

ln (\frac{1.2}{1.5})

- ln (60 - X) + ln (150 - X)

10 \cdot lo g_{e} (\frac{e - 1}{e})

What is simplify-ln(n+1)+ln(n-1) ?
The solution to simplify-ln(n+1)+ln(n-1) is ln((n-1)/(n+1))