What is simplify-log_{10}(7.15x10^{-5}) ?

The solution to simplify-log_{10}(7.15x10^{-5}) is -log_{10}(7.15)-log_{10}(x)+5

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simplify-log_{10}(7.15x10^{-5})

simplify

- lo g_{10} (7.15 x 1 0^{- 5})

- lo g_{10} (7.15) - lo g_{10} (x) + 5

Solution steps

- lo g_{10} (7.15 x \cdot 1 0^{- 5})

Apply log rule:

lo g_{c} (ab) = lo g_{c} (a) + lo g_{c} (b)

lo g_{10} (7.15 x \cdot 1 0^{- 5}) = lo g_{10} (7.15) + lo g_{10} (x) + lo g_{10} (1 0^{- 5})

= - (lo g_{10} (x) + lo g_{10} (7.15) + lo g_{10} (1 0^{- 5}))

Apply log rule:

lo g_{a} (x^{b}) = b \cdot lo g_{a} (x)

lo g_{10} (1 0^{- 5}) = - 5 lo g_{10} (10)

= - (lo g_{10} (7.15) + lo g_{10} (x) - 5 lo g_{10} (10))

5 lo g_{10} (10) = 5

= - (lo g_{10} (x) + lo g_{10} (7.15) - 5)

Distribute parentheses

= - (lo g_{10} (7.15)) - (lo g_{10} (x)) - (- 5)

Apply minus-plus rules

- (- a) = a, - (a) = - a

= - lo g_{10} (7.15) - lo g_{10} (x) + 5

3 lo g_{10} (x) - 2 lo g_{10} (x + 4)

ln (2 x + 2) - ln (x + 2)

\frac{19.15}{3219 \cdot 0.02} ln (\frac{1}{1 - 0.9})

ln (3 x) - x (\frac{1}{x})

- lo g_{10} (2.85 \cdot 1 0^{- 2})

What is simplify-log_{10}(7.15x10^{-5}) ?
The solution to simplify-log_{10}(7.15x10^{-5}) is -log_{10}(7.15)-log_{10}(x)+5