What are the solutions to the equation x^2+3x-68=3x-4 ?

The solutions to the equation x^2+3x-68=3x-4 are x=8,x=-8

Find the zeros of x^2+3x-68=3x-4

The zeros of x^2+3x-68=3x-4 are x=8,x=-8

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x^{2} + 3 x - 68 = 3 x - 4

x = 8, x = - 8

Solution steps

x^{2} + 3 x - 68 = 3 x - 4

Move

68

to the right side

x^{2} + 3 x = 3 x + 64

Move

3 x

to the left side

x^{2} = 64

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 64, x = - 64

64 = 8

- 64 = - 8

x = 8, x = - 8

x^{2} - 8 x = - x

x^{2} - 10 x - 4 = - 2 x - 4

A (x) = x (\frac{288 - 2 x}{2})

(2 x + 1) (4 x^{2} - 2 x + 1) - 1 = 1.6 x^{2} (5 x - 2)

9 x^{2} - 12 x + 5

What are the solutions to the equation x^2+3x-68=3x-4 ?
The solutions to the equation x^2+3x-68=3x-4 are x=8,x=-8
Find the zeros of x^2+3x-68=3x-4
The zeros of x^2+3x-68=3x-4 are x=8,x=-8