What are the solutions to the equation 4v^2-4v-15=0 ?

The solutions to the equation 4v^2-4v-15=0 are v= 5/2 ,v=-3/2

Find the zeros of 4v^2-4v-15=0

The zeros of 4v^2-4v-15=0 are v= 5/2 ,v=-3/2

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4 v^{2} - 4 v - 15 = 0

v = \frac{5}{2}, v = - \frac{3}{2}

Decimal Notation

v = 2.5, v = - 1.5

Solution steps

4 v^{2} - 4 v - 15 = 0

Solve with the quadratic formula

v_{1, 2} = \frac{- ( - 4 ) \pm ( - 4 ) ^{2} - 4 \cdot 4 ( - 15 )}{2 \cdot 4}

(- 4)^{2} - 4 \cdot 4 (- 15) = 16

v_{1, 2} = \frac{- ( - 4 ) \pm 16}{2 \cdot 4}

Separate the solutions

v_{1} = \frac{- ( - 4 ) + 16}{2 \cdot 4}, v_{2} = \frac{- ( - 4 ) - 16}{2 \cdot 4}

v = \frac{- ( - 4 ) + 16}{2 \cdot 4} : \frac{5}{2}

v = \frac{- ( - 4 ) - 16}{2 \cdot 4} : - \frac{3}{2}

The solutions to the quadratic equation are:

v = \frac{5}{2}, v = - \frac{3}{2}

x^{2} + 5 x - 3 = - 4 x - 3

x^{2} - 8 x + 48 = 0

x^{2} - 14 = - 5

(x + 13)^{2} = (x + 12)^{2} + (x - 5)^{2}

4 (a^{2} - 3) = 6 a + 4 (a + 3)

What are the solutions to the equation 4v^2-4v-15=0 ?
The solutions to the equation 4v^2-4v-15=0 are v= 5/2 ,v=-3/2
Find the zeros of 4v^2-4v-15=0
The zeros of 4v^2-4v-15=0 are v= 5/2 ,v=-3/2