What are the solutions to the equation 4+b^2=2b ?

The solutions to the equation 4+b^2=2b are b=1+sqrt(3)i,b=1-sqrt(3)i

Find the zeros of 4+b^2=2b

The zeros of 4+b^2=2b are b=1+sqrt(3)i,b=1-sqrt(3)i

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4 + b^{2} = 2 b

b = 1 + 3 i, b = 1 - 3 i

Solution steps

4 + b^{2} = 2 b

Move

2 b

to the left side

4 + b^{2} - 2 b = 0

Write in the standard form

a x^{2} + b x + c = 0

b^{2} - 2 b + 4 = 0

Solve with the quadratic formula

b_{1, 2} = \frac{- ( - 2 ) \pm ( - 2 ) ^{2} - 4 \cdot 1 \cdot 4}{2 \cdot 1}

Simplify

(- 2)^{2} - 4 \cdot 1 \cdot 4 : 23 i

b_{1, 2} = \frac{- ( - 2 ) \pm 2 3 i}{2 \cdot 1}

Separate the solutions

b_{1} = \frac{- ( - 2 ) + 2 3 i}{2 \cdot 1}, b_{2} = \frac{- ( - 2 ) - 2 3 i}{2 \cdot 1}

b = \frac{- ( - 2 ) + 2 3 i}{2 \cdot 1} : 1 + 3 i

b = \frac{- ( - 2 ) - 2 3 i}{2 \cdot 1} : 1 - 3 i

The solutions to the quadratic equation are:

b = 1 + 3 i, b = 1 - 3 i

- 4 x^{2} = - 1

x^{2} - 9 x = - 26

(x + 5) (x - 1) = 16

a, (a - 1)^{2} + (b - 2)^{2} = 0

2 x^{2} - 4 x - 4 = 2 x + 3

What are the solutions to the equation 4+b^2=2b ?
The solutions to the equation 4+b^2=2b are b=1+sqrt(3)i,b=1-sqrt(3)i
Find the zeros of 4+b^2=2b
The zeros of 4+b^2=2b are b=1+sqrt(3)i,b=1-sqrt(3)i