What are the solutions to the equation x^2-9x=-26 ?

The solutions to the equation x^2-9x=-26 are x= 9/2+i(sqrt(23))/2 ,x= 9/2-i(sqrt(23))/2

Find the zeros of x^2-9x=-26

The zeros of x^2-9x=-26 are x= 9/2+i(sqrt(23))/2 ,x= 9/2-i(sqrt(23))/2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

x^{2} - 9 x = - 26

x = \frac{9}{2} + i \frac{23}{2}, x = \frac{9}{2} - i \frac{23}{2}

Solution steps

x^{2} - 9 x = - 26

Move

26

to the left side

x^{2} - 9 x + 26 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 9 ) \pm ( - 9 ) ^{2} - 4 \cdot 1 \cdot 26}{2 \cdot 1}

Simplify

(- 9)^{2} - 4 \cdot 1 \cdot 26 : 23 i

x_{1, 2} = \frac{- ( - 9 ) \pm 23 i}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 9 ) + 23 i}{2 \cdot 1}, x_{2} = \frac{- ( - 9 ) - 23 i}{2 \cdot 1}

x = \frac{- ( - 9 ) + 23 i}{2 \cdot 1} : \frac{9}{2} + i \frac{23}{2}

x = \frac{- ( - 9 ) - 23 i}{2 \cdot 1} : \frac{9}{2} - i \frac{23}{2}

The solutions to the quadratic equation are:

x = \frac{9}{2} + i \frac{23}{2}, x = \frac{9}{2} - i \frac{23}{2}

(x + 5) (x - 1) = 16

a, (a - 1)^{2} + (b - 2)^{2} = 0

2 x^{2} - 4 x - 4 = 2 x + 3

- r^{2} - 25 r + 20 = 0

x, f = 3 x y^{2} - 2 y + 5 x^{2} y^{2}

What are the solutions to the equation x^2-9x=-26 ?
The solutions to the equation x^2-9x=-26 are x= 9/2+i(sqrt(23))/2 ,x= 9/2-i(sqrt(23))/2
Find the zeros of x^2-9x=-26
The zeros of x^2-9x=-26 are x= 9/2+i(sqrt(23))/2 ,x= 9/2-i(sqrt(23))/2