What are the solutions to the equation 4b^2+2b-2=3b ?

The solutions to the equation 4b^2+2b-2=3b are b=(1+sqrt(33))/8 ,b=(1-sqrt(33))/8

Find the zeros of 4b^2+2b-2=3b

The zeros of 4b^2+2b-2=3b are b=(1+sqrt(33))/8 ,b=(1-sqrt(33))/8

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4 b^{2} + 2 b - 2 = 3 b

b = \frac{1 + 33}{8}, b = \frac{1 - 33}{8}

Decimal Notation

b = 0.84307 \dots, b = - 0.59307 \dots

Solution steps

4 b^{2} + 2 b - 2 = 3 b

Move

3 b

to the left side

4 b^{2} - b - 2 = 0

Solve with the quadratic formula

b_{1, 2} = \frac{- ( - 1 ) \pm ( - 1 ) ^{2} - 4 \cdot 4 ( - 2 )}{2 \cdot 4}

(- 1)^{2} - 4 \cdot 4 (- 2) = 33

b_{1, 2} = \frac{- ( - 1 ) \pm 33}{2 \cdot 4}

Separate the solutions

b_{1} = \frac{- ( - 1 ) + 33}{2 \cdot 4}, b_{2} = \frac{- ( - 1 ) - 33}{2 \cdot 4}

b = \frac{- ( - 1 ) + 33}{2 \cdot 4} : \frac{1 + 33}{8}

b = \frac{- ( - 1 ) - 33}{2 \cdot 4} : \frac{1 - 33}{8}

The solutions to the quadratic equation are:

b = \frac{1 + 33}{8}, b = \frac{1 - 33}{8}

x^{2} - 9 x - 9 = - 5 x - 4

8 c^{2} + 18 c - 7 = - 2

x, 9 x^{2} + 16 y^{2} + 36 x - 100 y = - 292

x^{2} + x - 16 = x

ab (x^{2} - c^{2}) = (a^{2} - b^{2}) c x

What are the solutions to the equation 4b^2+2b-2=3b ?
The solutions to the equation 4b^2+2b-2=3b are b=(1+sqrt(33))/8 ,b=(1-sqrt(33))/8
Find the zeros of 4b^2+2b-2=3b
The zeros of 4b^2+2b-2=3b are b=(1+sqrt(33))/8 ,b=(1-sqrt(33))/8