What are the solutions to the equation 1-0.75x+0.1x^2=0 ?

The solutions to the equation 1-0.75x+0.1x^2=0 are x=(15+sqrt(65))/4 ,x=(15-sqrt(65))/4

Find the zeros of 1-0.75x+0.1x^2=0

The zeros of 1-0.75x+0.1x^2=0 are x=(15+sqrt(65))/4 ,x=(15-sqrt(65))/4

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1 - 0.75 x + 0.1 x^{2} = 0

x = \frac{15 + 65}{4}, x = \frac{15 - 65}{4}

Decimal Notation

x = 5.76556 \dots, x = 1.73443 \dots

Solution steps

1 - 0.75 x + 0.1 x^{2} = 0

Multiply both sides by

100

100 - 75 x + 10 x^{2} = 0

Write in the standard form

a x^{2} + b x + c = 0

10 x^{2} - 75 x + 100 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 75 ) \pm ( - 75 ) ^{2} - 4 \cdot 10 \cdot 100}{2 \cdot 10}

(- 75)^{2} - 4 \cdot 10 \cdot 100 = 565

x_{1, 2} = \frac{- ( - 75 ) \pm 5 65}{2 \cdot 10}

Separate the solutions

x_{1} = \frac{- ( - 75 ) + 5 65}{2 \cdot 10}, x_{2} = \frac{- ( - 75 ) - 5 65}{2 \cdot 10}

x = \frac{- ( - 75 ) + 5 65}{2 \cdot 10} : \frac{15 + 65}{4}

x = \frac{- ( - 75 ) - 5 65}{2 \cdot 10} : \frac{15 - 65}{4}

The solutions to the quadratic equation are:

x = \frac{15 + 65}{4}, x = \frac{15 - 65}{4}

x^{0} = x^{2} + 5 x + 8

x, d^{2} = 2 x^{2} + 2 x^{2}

a, 4 a^{2} - 6 ab = 0

3 x^{2} + 8 x - 10 = - 8

x^{2} + 12 x = 10

What are the solutions to the equation 1-0.75x+0.1x^2=0 ?
The solutions to the equation 1-0.75x+0.1x^2=0 are x=(15+sqrt(65))/4 ,x=(15-sqrt(65))/4
Find the zeros of 1-0.75x+0.1x^2=0
The zeros of 1-0.75x+0.1x^2=0 are x=(15+sqrt(65))/4 ,x=(15-sqrt(65))/4