What are the solutions to the equation x^0=x^2+5x+8 ?

The solutions to the equation x^0=x^2+5x+8 are x=-5/2+i(sqrt(3))/2 ,x=-5/2-i(sqrt(3))/2

Find the zeros of x^0=x^2+5x+8

The zeros of x^0=x^2+5x+8 are x=-5/2+i(sqrt(3))/2 ,x=-5/2-i(sqrt(3))/2

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x^{0} = x^{2} + 5 x + 8

x = - \frac{5}{2} + i \frac{3}{2}, x = - \frac{5}{2} - i \frac{3}{2}

Solution steps

x^{0} = x^{2} + 5 x + 8

Refine

1 = x^{2} + 5 x + 8

Switch sides

x^{2} + 5 x + 8 = 1

Move

1

to the left side

x^{2} + 5 x + 7 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 5 \pm 5 ^{2} - 4 \cdot 1 \cdot 7}{2 \cdot 1}

Simplify

5^{2} - 4 \cdot 1 \cdot 7 : 3 i

x_{1, 2} = \frac{- 5 \pm 3 i}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 5 + 3 i}{2 \cdot 1}, x_{2} = \frac{- 5 - 3 i}{2 \cdot 1}

x = \frac{- 5 + 3 i}{2 \cdot 1} : - \frac{5}{2} + i \frac{3}{2}

x = \frac{- 5 - 3 i}{2 \cdot 1} : - \frac{5}{2} - i \frac{3}{2}

The solutions to the quadratic equation are:

x = - \frac{5}{2} + i \frac{3}{2}, x = - \frac{5}{2} - i \frac{3}{2}

x, d^{2} = 2 x^{2} + 2 x^{2}

a, 4 a^{2} - 6 ab = 0

3 x^{2} + 8 x - 10 = - 8

x^{2} + 12 x = 10

x^{2} - 15 x = - 8 x + 18

What are the solutions to the equation x^0=x^2+5x+8 ?
The solutions to the equation x^0=x^2+5x+8 are x=-5/2+i(sqrt(3))/2 ,x=-5/2-i(sqrt(3))/2
Find the zeros of x^0=x^2+5x+8
The zeros of x^0=x^2+5x+8 are x=-5/2+i(sqrt(3))/2 ,x=-5/2-i(sqrt(3))/2