What are the solutions to the equation 3x^2+8x-10=-8 ?

The solutions to the equation 3x^2+8x-10=-8 are x=(-4+sqrt(22))/3 ,x=-(4+sqrt(22))/3

Find the zeros of 3x^2+8x-10=-8

The zeros of 3x^2+8x-10=-8 are x=(-4+sqrt(22))/3 ,x=-(4+sqrt(22))/3

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

3 x^{2} + 8 x - 10 = - 8

x = \frac{- 4 + 22}{3}, x = - \frac{4 + 22}{3}

Decimal Notation

x = 0.23013 \dots, x = - 2.89680 \dots

Solution steps

3 x^{2} + 8 x - 10 = - 8

Move

8

to the left side

3 x^{2} + 8 x - 2 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 8 \pm 8 ^{2} - 4 \cdot 3 ( - 2 )}{2 \cdot 3}

8^{2} - 4 \cdot 3 (- 2) = 222

x_{1, 2} = \frac{- 8 \pm 2 22}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- 8 + 2 22}{2 \cdot 3}, x_{2} = \frac{- 8 - 2 22}{2 \cdot 3}

x = \frac{- 8 + 2 22}{2 \cdot 3} : \frac{- 4 + 22}{3}

x = \frac{- 8 - 2 22}{2 \cdot 3} : - \frac{4 + 22}{3}

The solutions to the quadratic equation are:

x = \frac{- 4 + 22}{3}, x = - \frac{4 + 22}{3}

x^{2} + 12 x = 10

x^{2} - 15 x = - 8 x + 18

(x + 1)^{2} - 2 x = - 2 x

- 2 x^{2} + 60 x - 120 = 0

3 n^{2} + 17 n + 17 = - 2

What are the solutions to the equation 3x^2+8x-10=-8 ?
The solutions to the equation 3x^2+8x-10=-8 are x=(-4+sqrt(22))/3 ,x=-(4+sqrt(22))/3
Find the zeros of 3x^2+8x-10=-8
The zeros of 3x^2+8x-10=-8 are x=(-4+sqrt(22))/3 ,x=-(4+sqrt(22))/3