What are the solutions to the equation 26x^2+41x+20=6x^2 ?

The solutions to the equation 26x^2+41x+20=6x^2 are x=-4/5 ,x=-5/4

Find the zeros of 26x^2+41x+20=6x^2

The zeros of 26x^2+41x+20=6x^2 are x=-4/5 ,x=-5/4

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26 x^{2} + 41 x + 20 = 6 x^{2}

x = - \frac{4}{5}, x = - \frac{5}{4}

Decimal Notation

x = - 0.8, x = - 1.25

Solution steps

26 x^{2} + 41 x + 20 = 6 x^{2}

Move

6 x^{2}

to the left side

20 x^{2} + 41 x + 20 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 41 \pm 4 1 ^{2} - 4 \cdot 20 \cdot 20}{2 \cdot 20}

4 1^{2} - 4 \cdot 20 \cdot 20 = 9

x_{1, 2} = \frac{- 41 \pm 9}{2 \cdot 20}

Separate the solutions

x_{1} = \frac{- 41 + 9}{2 \cdot 20}, x_{2} = \frac{- 41 - 9}{2 \cdot 20}

x = \frac{- 41 + 9}{2 \cdot 20} : - \frac{4}{5}

x = \frac{- 41 - 9}{2 \cdot 20} : - \frac{5}{4}

The solutions to the quadratic equation are:

x = - \frac{4}{5}, x = - \frac{5}{4}

- 0.00015 x^{2} - 0.001652 x + 0.0153 = 0

4 - x^{2} = x^{2}

5 (x - 3) - x (x - 3) = 0

12 x^{2} = 4 x

5 q^{2} + 7 q - 1 = 0

What are the solutions to the equation 26x^2+41x+20=6x^2 ?
The solutions to the equation 26x^2+41x+20=6x^2 are x=-4/5 ,x=-5/4
Find the zeros of 26x^2+41x+20=6x^2
The zeros of 26x^2+41x+20=6x^2 are x=-4/5 ,x=-5/4