What are the solutions to the equation (4x+3)^2=16 ?

The solutions to the equation (4x+3)^2=16 are x= 1/4 ,x=-7/4

Find the zeros of (4x+3)^2=16

The zeros of (4x+3)^2=16 are x= 1/4 ,x=-7/4

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(4 x + 3)^{2} = 16

x = \frac{1}{4}, x = - \frac{7}{4}

Decimal Notation

x = 0.25, x = - 1.75

Solution steps

(4 x + 3)^{2} = 16

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

4 x + 3 = 16 : x = \frac{1}{4}

Solve

4 x + 3 = - 16 : x = - \frac{7}{4}

The solutions to the quadratic equation are:

x = \frac{1}{4}, x = - \frac{7}{4}

5 b^{2} + 24 b - 3 = 2

3 x^{2} + 4 x + 9 = 8

(9 x + 4)^{2} = 72 x + 25

5529 x^{2} - 18634 x + 8841 = 0

25 n^{2} - 15 n + 4 = 5 n

What are the solutions to the equation (4x+3)^2=16 ?
The solutions to the equation (4x+3)^2=16 are x= 1/4 ,x=-7/4
Find the zeros of (4x+3)^2=16
The zeros of (4x+3)^2=16 are x= 1/4 ,x=-7/4