What are the solutions to the equation 5p^2-13p+6=p^2 ?

The solutions to the equation 5p^2-13p+6=p^2 are p=(13+sqrt(73))/8 ,p=(13-sqrt(73))/8

Find the zeros of 5p^2-13p+6=p^2

The zeros of 5p^2-13p+6=p^2 are p=(13+sqrt(73))/8 ,p=(13-sqrt(73))/8

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5 p^{2} - 13 p + 6 = p^{2}

p = \frac{13 + 73}{8}, p = \frac{13 - 73}{8}

Decimal Notation

p = 2.69300 \dots, p = 0.55699 \dots

Solution steps

5 p^{2} - 13 p + 6 = p^{2}

Move

p^{2}

to the left side

4 p^{2} - 13 p + 6 = 0

Solve with the quadratic formula

p_{1, 2} = \frac{- ( - 13 ) \pm ( - 13 ) ^{2} - 4 \cdot 4 \cdot 6}{2 \cdot 4}

(- 13)^{2} - 4 \cdot 4 \cdot 6 = 73

p_{1, 2} = \frac{- ( - 13 ) \pm 73}{2 \cdot 4}

Separate the solutions

p_{1} = \frac{- ( - 13 ) + 73}{2 \cdot 4}, p_{2} = \frac{- ( - 13 ) - 73}{2 \cdot 4}

p = \frac{- ( - 13 ) + 73}{2 \cdot 4} : \frac{13 + 73}{8}

p = \frac{- ( - 13 ) - 73}{2 \cdot 4} : \frac{13 - 73}{8}

The solutions to the quadratic equation are:

p = \frac{13 + 73}{8}, p = \frac{13 - 73}{8}

2 x^{2} + 7 x - 7 = 2

x, x^{2} + y^{2} + z^{2} = z

2 x^{2} - 10 - 8 x = 0

4 x^{2} + 140 x - 296 = 0

x, x^{2} - y^{2} = a^{2}

What are the solutions to the equation 5p^2-13p+6=p^2 ?
The solutions to the equation 5p^2-13p+6=p^2 are p=(13+sqrt(73))/8 ,p=(13-sqrt(73))/8
Find the zeros of 5p^2-13p+6=p^2
The zeros of 5p^2-13p+6=p^2 are p=(13+sqrt(73))/8 ,p=(13-sqrt(73))/8