What are the solutions to the equation 2x^2+7x-7=2 ?

The solutions to the equation 2x^2+7x-7=2 are x=1,x=-9/2

Find the zeros of 2x^2+7x-7=2

The zeros of 2x^2+7x-7=2 are x=1,x=-9/2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

2 x^{2} + 7 x - 7 = 2

x = 1, x = - \frac{9}{2}

Decimal Notation

x = 1, x = - 4.5

Solution steps

2 x^{2} + 7 x - 7 = 2

Move

2

to the left side

2 x^{2} + 7 x - 9 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 7 \pm 7 ^{2} - 4 \cdot 2 ( - 9 )}{2 \cdot 2}

7^{2} - 4 \cdot 2 (- 9) = 11

x_{1, 2} = \frac{- 7 \pm 11}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- 7 + 11}{2 \cdot 2}, x_{2} = \frac{- 7 - 11}{2 \cdot 2}

x = \frac{- 7 + 11}{2 \cdot 2} : 1

x = \frac{- 7 - 11}{2 \cdot 2} : - \frac{9}{2}

The solutions to the quadratic equation are:

x = 1, x = - \frac{9}{2}

x, x^{2} + y^{2} + z^{2} = z

2 x^{2} - 10 - 8 x = 0

4 x^{2} + 140 x - 296 = 0

x, x^{2} - y^{2} = a^{2}

- p^{2} + 5 p + 6 = - 2 p^{2}

What are the solutions to the equation 2x^2+7x-7=2 ?
The solutions to the equation 2x^2+7x-7=2 are x=1,x=-9/2
Find the zeros of 2x^2+7x-7=2
The zeros of 2x^2+7x-7=2 are x=1,x=-9/2