What are the solutions to the equation 2x^2-mx+n=0 ?

The solutions to the equation 2x^2-mx+n=0 are x=(m+sqrt(m^2-8n))/4 ,x=(m-sqrt(m^2-8n))/4

Find the zeros of 2x^2-mx+n=0

The zeros of 2x^2-mx+n=0 are x=(m+sqrt(m^2-8n))/4 ,x=(m-sqrt(m^2-8n))/4

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2 x^{2} - m x + n = 0

x = \frac{m + m ^{2} - 8 n}{4}, x = \frac{m - m ^{2} - 8 n}{4}

Solution steps

2 x^{2} - m x + n = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - m ) \pm ( - m ) ^{2} - 4 \cdot 2 n}{2 \cdot 2}

Simplify

(- m)^{2} - 4 \cdot 2 n : m^{2} - 8 n

x_{1, 2} = \frac{- ( - m ) \pm m ^{2} - 8 n}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- ( - m ) + m ^{2} - 8 n}{2 \cdot 2}, x_{2} = \frac{- ( - m ) - m ^{2} - 8 n}{2 \cdot 2}

x = \frac{- ( - m ) + m ^{2} - 8 n}{2 \cdot 2} : \frac{m + m ^{2} - 8 n}{4}

x = \frac{- ( - m ) - m ^{2} - 8 n}{2 \cdot 2} : \frac{m - m ^{2} - 8 n}{4}

The solutions to the quadratic equation are:

x = \frac{m + m ^{2} - 8 n}{4}, x = \frac{m - m ^{2} - 8 n}{4}

x, 3 x^{2} + 3 y^{2} + 3 z^{2} + 2 y - 2 z = 9

3 x^{2} - 5 x = - 8

z^{2} + 2 z - 15 = - 3 z

(2 x - 1)^{2} - (x - 3) (x + 5) = (2 x + 3) (2 x - 3)

3 x^{2} + 7 x + 5 = 3 x + 4

What are the solutions to the equation 2x^2-mx+n=0 ?
The solutions to the equation 2x^2-mx+n=0 are x=(m+sqrt(m^2-8n))/4 ,x=(m-sqrt(m^2-8n))/4
Find the zeros of 2x^2-mx+n=0
The zeros of 2x^2-mx+n=0 are x=(m+sqrt(m^2-8n))/4 ,x=(m-sqrt(m^2-8n))/4