What are the solutions to the equation 3x^2-5x=-8 ?

The solutions to the equation 3x^2-5x=-8 are x= 5/6+i(sqrt(71))/6 ,x= 5/6-i(sqrt(71))/6

Find the zeros of 3x^2-5x=-8

The zeros of 3x^2-5x=-8 are x= 5/6+i(sqrt(71))/6 ,x= 5/6-i(sqrt(71))/6

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3 x^{2} - 5 x = - 8

x = \frac{5}{6} + i \frac{71}{6}, x = \frac{5}{6} - i \frac{71}{6}

Solution steps

3 x^{2} - 5 x = - 8

Move

8

to the left side

3 x^{2} - 5 x + 8 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 5 ) \pm ( - 5 ) ^{2} - 4 \cdot 3 \cdot 8}{2 \cdot 3}

Simplify

(- 5)^{2} - 4 \cdot 3 \cdot 8 : 71 i

x_{1, 2} = \frac{- ( - 5 ) \pm 71 i}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- ( - 5 ) + 71 i}{2 \cdot 3}, x_{2} = \frac{- ( - 5 ) - 71 i}{2 \cdot 3}

x = \frac{- ( - 5 ) + 71 i}{2 \cdot 3} : \frac{5}{6} + i \frac{71}{6}

x = \frac{- ( - 5 ) - 71 i}{2 \cdot 3} : \frac{5}{6} - i \frac{71}{6}

The solutions to the quadratic equation are:

x = \frac{5}{6} + i \frac{71}{6}, x = \frac{5}{6} - i \frac{71}{6}

z^{2} + 2 z - 15 = - 3 z

(2 x - 1)^{2} - (x - 3) (x + 5) = (2 x + 3) (2 x - 3)

3 x^{2} + 7 x + 5 = 3 x + 4

x, 3 y x^{2} - x^{2} + 3 = 0

x^{2} + 8 x + 8 + 8 = 0

What are the solutions to the equation 3x^2-5x=-8 ?
The solutions to the equation 3x^2-5x=-8 are x= 5/6+i(sqrt(71))/6 ,x= 5/6-i(sqrt(71))/6
Find the zeros of 3x^2-5x=-8
The zeros of 3x^2-5x=-8 are x= 5/6+i(sqrt(71))/6 ,x= 5/6-i(sqrt(71))/6