What are the solutions to the equation 3x^2+7x+5=3x+4 ?

The solutions to the equation 3x^2+7x+5=3x+4 are x=-1/3 ,x=-1

Find the zeros of 3x^2+7x+5=3x+4

The zeros of 3x^2+7x+5=3x+4 are x=-1/3 ,x=-1

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3 x^{2} + 7 x + 5 = 3 x + 4

x = - \frac{1}{3}, x = - 1

Decimal Notation

x = - 0.33333 \dots, x = - 1

Solution steps

3 x^{2} + 7 x + 5 = 3 x + 4

Move

4

to the left side

3 x^{2} + 7 x + 1 = 3 x

Move

3 x

to the left side

3 x^{2} + 4 x + 1 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 \cdot 3 \cdot 1}{2 \cdot 3}

4^{2} - 4 \cdot 3 \cdot 1 = 2

x_{1, 2} = \frac{- 4 \pm 2}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- 4 + 2}{2 \cdot 3}, x_{2} = \frac{- 4 - 2}{2 \cdot 3}

x = \frac{- 4 + 2}{2 \cdot 3} : - \frac{1}{3}

x = \frac{- 4 - 2}{2 \cdot 3} : - 1

The solutions to the quadratic equation are:

x = - \frac{1}{3}, x = - 1

x, 3 y x^{2} - x^{2} + 3 = 0

x^{2} + 8 x + 8 + 8 = 0

x, x^{2} + y^{2} = 10 x - 6 y - 34

(x - 6) (x + 2) = 9

(4 y - 3)^{2} = 72

What are the solutions to the equation 3x^2+7x+5=3x+4 ?
The solutions to the equation 3x^2+7x+5=3x+4 are x=-1/3 ,x=-1
Find the zeros of 3x^2+7x+5=3x+4
The zeros of 3x^2+7x+5=3x+4 are x=-1/3 ,x=-1