What are the solutions to the equation x^2+8x+8+8=0 ?

The solutions to the equation x^2+8x+8+8=0 are x=-4

Find the zeros of x^2+8x+8+8=0

The zeros of x^2+8x+8+8=0 are x=-4

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x^{2} + 8 x + 8 + 8 = 0

x = - 4

Solution steps

x^{2} + 8 x + 8 + 8 = 0

Refine

x^{2} + 8 x + 16 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 8 \pm 8 ^{2} - 4 \cdot 1 \cdot 16}{2 \cdot 1}

8^{2} - 4 \cdot 1 \cdot 16 = 0

x_{1, 2} = \frac{- 8 \pm 0}{2 \cdot 1}

x = \frac{- 8}{2 \cdot 1}

\frac{- 8}{2 \cdot 1} = - 4

x = - 4

The solution to the quadratic equation is:

x = - 4

x, x^{2} + y^{2} = 10 x - 6 y - 34

(x - 6) (x + 2) = 9

(4 y - 3)^{2} = 72

y^{2} - 7 y = - 12

3 x^{2} = - 9 x + 2

What are the solutions to the equation x^2+8x+8+8=0 ?
The solutions to the equation x^2+8x+8+8=0 are x=-4
Find the zeros of x^2+8x+8+8=0
The zeros of x^2+8x+8+8=0 are x=-4