What are the solutions to the equation (4y-3)^2=72 ?

The solutions to the equation (4y-3)^2=72 are y=(6sqrt(2)+3)/4 ,y=(-6sqrt(2)+3)/4

Find the zeros of (4y-3)^2=72

The zeros of (4y-3)^2=72 are y=(6sqrt(2)+3)/4 ,y=(-6sqrt(2)+3)/4

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(4 y - 3)^{2} = 72

y = \frac{6 2 + 3}{4}, y = \frac{- 6 2 + 3}{4}

Decimal Notation

y = 2.87132 \dots, y = - 1.37132 \dots

Solution steps

(4 y - 3)^{2} = 72

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

4 y - 3 = 72 : y = \frac{6 2 + 3}{4}

Solve

4 y - 3 = - 72 : y = \frac{- 6 2 + 3}{4}

The solutions to the quadratic equation are:

y = \frac{6 2 + 3}{4}, y = \frac{- 6 2 + 3}{4}

y^{2} - 7 y = - 12

3 x^{2} = - 9 x + 2

x, x^{2} + y^{2} - 4 x - 2 y + 17 = 0

- 2 x^{2} - 3 x + 7 = 0

3 b^{2} - 7 b + 3 = 6

What are the solutions to the equation (4y-3)^2=72 ?
The solutions to the equation (4y-3)^2=72 are y=(6sqrt(2)+3)/4 ,y=(-6sqrt(2)+3)/4
Find the zeros of (4y-3)^2=72
The zeros of (4y-3)^2=72 are y=(6sqrt(2)+3)/4 ,y=(-6sqrt(2)+3)/4