What are the solutions to the equation 5+3c^2=17 ?

The solutions to the equation 5+3c^2=17 are c=2,c=-2

Find the zeros of 5+3c^2=17

The zeros of 5+3c^2=17 are c=2,c=-2

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5 + 3 c^{2} = 17

c = 2, c = - 2

Solution steps

5 + 3 c^{2} = 17

Move

5

to the right side

3 c^{2} = 12

Divide both sides by

3

c^{2} = 4

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

c = 4, c = - 4

4 = 2

- 4 = - 2

c = 2, c = - 2

24 π r - \frac{9 π}{2} r^{2} = 0

q^{2} - q - 10 = 2 q

4 y^{2} + 11 y + 3 = - 1

v, \frac{m v ^{2}}{r} = q v B

5 x^{2} + 14 x = x + 6

What are the solutions to the equation 5+3c^2=17 ?
The solutions to the equation 5+3c^2=17 are c=2,c=-2
Find the zeros of 5+3c^2=17
The zeros of 5+3c^2=17 are c=2,c=-2