What are the solutions to the equation x*(20x-21)=27 ?

The solutions to the equation x*(20x-21)=27 are x= 9/5 ,x=-3/4

Find the zeros of x*(20x-21)=27

The zeros of x*(20x-21)=27 are x= 9/5 ,x=-3/4

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x \cdot (20 x - 21) = 27

x = \frac{9}{5}, x = - \frac{3}{4}

Decimal Notation

x = 1.8, x = - 0.75

Solution steps

x (20 x - 21) = 27

Expand

x (20 x - 21) : 20 x^{2} - 21 x

20 x^{2} - 21 x = 27

Move

27

to the left side

20 x^{2} - 21 x - 27 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 21 ) \pm ( - 21 ) ^{2} - 4 \cdot 20 ( - 27 )}{2 \cdot 20}

(- 21)^{2} - 4 \cdot 20 (- 27) = 51

x_{1, 2} = \frac{- ( - 21 ) \pm 51}{2 \cdot 20}

Separate the solutions

x_{1} = \frac{- ( - 21 ) + 51}{2 \cdot 20}, x_{2} = \frac{- ( - 21 ) - 51}{2 \cdot 20}

x = \frac{- ( - 21 ) + 51}{2 \cdot 20} : \frac{9}{5}

x = \frac{- ( - 21 ) - 51}{2 \cdot 20} : - \frac{3}{4}

The solutions to the quadratic equation are:

x = \frac{9}{5}, x = - \frac{3}{4}

D = (2 a - 3)^{2} - (a + 5) (a - 5) + \frac{6 a + 68}{2}

15 z^{2} + 6 z - 8 = 4 z

- 0.03 q^{2} + 975 = 35 q + 263

2 x^{2} - 4 x + 7

x, y = x^{2} + y

What are the solutions to the equation x*(20x-21)=27 ?
The solutions to the equation x*(20x-21)=27 are x= 9/5 ,x=-3/4
Find the zeros of x*(20x-21)=27
The zeros of x*(20x-21)=27 are x= 9/5 ,x=-3/4