What are the solutions to the equation 15z^2+6z-8=4z ?

The solutions to the equation 15z^2+6z-8=4z are z= 2/3 ,z=-4/5

Find the zeros of 15z^2+6z-8=4z

The zeros of 15z^2+6z-8=4z are z= 2/3 ,z=-4/5

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15 z^{2} + 6 z - 8 = 4 z

z = \frac{2}{3}, z = - \frac{4}{5}

Decimal Notation

z = 0.66666 \dots, z = - 0.8

Solution steps

15 z^{2} + 6 z - 8 = 4 z

Move

4 z

to the left side

15 z^{2} + 2 z - 8 = 0

Solve with the quadratic formula

z_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 \cdot 15 ( - 8 )}{2 \cdot 15}

2^{2} - 4 \cdot 15 (- 8) = 22

z_{1, 2} = \frac{- 2 \pm 22}{2 \cdot 15}

Separate the solutions

z_{1} = \frac{- 2 + 22}{2 \cdot 15}, z_{2} = \frac{- 2 - 22}{2 \cdot 15}

z = \frac{- 2 + 22}{2 \cdot 15} : \frac{2}{3}

z = \frac{- 2 - 22}{2 \cdot 15} : - \frac{4}{5}

The solutions to the quadratic equation are:

z = \frac{2}{3}, z = - \frac{4}{5}

- 0.03 q^{2} + 975 = 35 q + 263

2 x^{2} - 4 x + 7

x, y = x^{2} + y

a, a^{2} - 2 ab + 4 b^{2} = 0

- 0.5 x^{2} + 50 x - 600 = 0

What are the solutions to the equation 15z^2+6z-8=4z ?
The solutions to the equation 15z^2+6z-8=4z are z= 2/3 ,z=-4/5
Find the zeros of 15z^2+6z-8=4z
The zeros of 15z^2+6z-8=4z are z= 2/3 ,z=-4/5