What are the solutions to the equation 5b^2+15b+8=0 ?

The solutions to the equation 5b^2+15b+8=0 are b=(-15+sqrt(65))/(10),b=(-15-sqrt(65))/(10)

Find the zeros of 5b^2+15b+8=0

The zeros of 5b^2+15b+8=0 are b=(-15+sqrt(65))/(10),b=(-15-sqrt(65))/(10)

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5 b^{2} + 15 b + 8 = 0

b = \frac{- 15 + 65}{10}, b = \frac{- 15 - 65}{10}

Decimal Notation

b = - 0.69377 \dots, b = - 2.30622 \dots

Solution steps

5 b^{2} + 15 b + 8 = 0

Solve with the quadratic formula

b_{1, 2} = \frac{- 15 \pm 1 5 ^{2} - 4 \cdot 5 \cdot 8}{2 \cdot 5}

1 5^{2} - 4 \cdot 5 \cdot 8 = 65

b_{1, 2} = \frac{- 15 \pm 65}{2 \cdot 5}

Separate the solutions

b_{1} = \frac{- 15 + 65}{2 \cdot 5}, b_{2} = \frac{- 15 - 65}{2 \cdot 5}

b = \frac{- 15 + 65}{2 \cdot 5} : \frac{- 15 + 65}{10}

b = \frac{- 15 - 65}{2 \cdot 5} : \frac{- 15 - 65}{10}

The solutions to the quadratic equation are:

b = \frac{- 15 + 65}{10}, b = \frac{- 15 - 65}{10}

m^{2} + 1 = 3

x^{2} + 6 x + 41 = 0

4 k^{2} - 4 k = 0

x^{2} - 7 x = 4

x, y^{3} = 1 - x^{2}

What are the solutions to the equation 5b^2+15b+8=0 ?
The solutions to the equation 5b^2+15b+8=0 are b=(-15+sqrt(65))/(10),b=(-15-sqrt(65))/(10)
Find the zeros of 5b^2+15b+8=0
The zeros of 5b^2+15b+8=0 are b=(-15+sqrt(65))/(10),b=(-15-sqrt(65))/(10)