What are the solutions to the equation 20x^2-26x+8=0 ?

The solutions to the equation 20x^2-26x+8=0 are x= 4/5 ,x= 1/2

Find the zeros of 20x^2-26x+8=0

The zeros of 20x^2-26x+8=0 are x= 4/5 ,x= 1/2

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20 x^{2} - 26 x + 8 = 0

x = \frac{4}{5}, x = \frac{1}{2}

Decimal Notation

x = 0.8, x = 0.5

Solution steps

20 x^{2} - 26 x + 8 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 26 ) \pm ( - 26 ) ^{2} - 4 \cdot 20 \cdot 8}{2 \cdot 20}

(- 26)^{2} - 4 \cdot 20 \cdot 8 = 6

x_{1, 2} = \frac{- ( - 26 ) \pm 6}{2 \cdot 20}

Separate the solutions

x_{1} = \frac{- ( - 26 ) + 6}{2 \cdot 20}, x_{2} = \frac{- ( - 26 ) - 6}{2 \cdot 20}

x = \frac{- ( - 26 ) + 6}{2 \cdot 20} : \frac{4}{5}

x = \frac{- ( - 26 ) - 6}{2 \cdot 20} : \frac{1}{2}

The solutions to the quadratic equation are:

x = \frac{4}{5}, x = \frac{1}{2}

x^{2} - \frac{11}{3} x - 2 = 0

25 k^{2} + 20 k + 3 = - 1

x, 2 x^{2} y - 2 x y = 0

y, x^{3} + x y^{2} - 2 y^{2} = 0

A x^{2} + 2 x + 3 = x^{2} - B x + C

What are the solutions to the equation 20x^2-26x+8=0 ?
The solutions to the equation 20x^2-26x+8=0 are x= 4/5 ,x= 1/2
Find the zeros of 20x^2-26x+8=0
The zeros of 20x^2-26x+8=0 are x= 4/5 ,x= 1/2