What are the solutions to the equation 4p^2+6p+1=2p ?

The solutions to the equation 4p^2+6p+1=2p are p=-1/2

Find the zeros of 4p^2+6p+1=2p

The zeros of 4p^2+6p+1=2p are p=-1/2

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4 p^{2} + 6 p + 1 = 2 p

p = - \frac{1}{2}

Decimal Notation

p = - 0.5

Solution steps

4 p^{2} + 6 p + 1 = 2 p

Move

2 p

to the left side

4 p^{2} + 4 p + 1 = 0

Solve with the quadratic formula

p_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 \cdot 4 \cdot 1}{2 \cdot 4}

4^{2} - 4 \cdot 4 \cdot 1 = 0

p_{1, 2} = \frac{- 4 \pm 0}{2 \cdot 4}

p = \frac{- 4}{2 \cdot 4}

\frac{- 4}{2 \cdot 4} = - \frac{1}{2}

p = - \frac{1}{2}

The solution to the quadratic equation is:

p = - \frac{1}{2}

- 16 x^{2} + 14 x + 4 = 0

- x^{2} + 6 x = - 1

9^{2} + x^{2} = 1 8^{2}

x^{2} + 55 = - 16 x - 5

2 x^{2} + 4 = 5 x + 2

What are the solutions to the equation 4p^2+6p+1=2p ?
The solutions to the equation 4p^2+6p+1=2p are p=-1/2
Find the zeros of 4p^2+6p+1=2p
The zeros of 4p^2+6p+1=2p are p=-1/2