What are the solutions to the equation 8x-2x^2=0 ?

The solutions to the equation 8x-2x^2=0 are x=0,x=4

Find the zeros of 8x-2x^2=0

The zeros of 8x-2x^2=0 are x=0,x=4

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8 x - 2 x^{2} = 0

x = 0, x = 4

Solution steps

8 x - 2 x^{2} = 0

Write in the standard form

a x^{2} + b x + c = 0

- 2 x^{2} + 8 x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 8 \pm 8 ^{2} - 4 ( - 2 ) \cdot 0}{2 ( - 2 )}

8^{2} - 4 (- 2) \cdot 0 = 8

x_{1, 2} = \frac{- 8 \pm 8}{2 ( - 2 )}

Separate the solutions

x_{1} = \frac{- 8 + 8}{2 ( - 2 )}, x_{2} = \frac{- 8 - 8}{2 ( - 2 )}

x = \frac{- 8 + 8}{2 ( - 2 )} : 0

x = \frac{- 8 - 8}{2 ( - 2 )} : 4

The solutions to the quadratic equation are:

x = 0, x = 4

2 x^{2} - x - 11 = 0

2 (x (x - 5) + 2 (x - 5) + 2 x (x - 5)) = 48

0.03 + 0.08 x - 0.012 x^{2} = 0

3600 = x^{2} - 160 x + 10000

x, \frac{x ^{2}}{3} + 3 y^{2} = 0

What are the solutions to the equation 8x-2x^2=0 ?
The solutions to the equation 8x-2x^2=0 are x=0,x=4
Find the zeros of 8x-2x^2=0
The zeros of 8x-2x^2=0 are x=0,x=4