What are the solutions to the equation (x+3)^2=2 ?

The solutions to the equation (x+3)^2=2 are x=sqrt(2)-3,x=-sqrt(2)-3

Find the zeros of (x+3)^2=2

The zeros of (x+3)^2=2 are x=sqrt(2)-3,x=-sqrt(2)-3

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(x + 3)^{2} = 2

x = 2 - 3, x = - 2 - 3

Decimal Notation

x = - 1.58578 \dots, x = - 4.41421 \dots

Solution steps

(x + 3)^{2} = 2

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x + 3 = 2 : x = 2 - 3

Solve

x + 3 = - 2 : x = - 2 - 3

The solutions to the quadratic equation are:

x = 2 - 3, x = - 2 - 3

x^{2} - 3 x - \frac{9}{4} = 12

2 x^{2} - 12 x + 17

3 x^{2} + x + 4 = - 9 x + 1

x, x^{2} + (1 - y)^{2} + 5 = 0

x, 7 x^{2} + 7 y^{2} - 2 x y - 6 x - 6 y = 9

What are the solutions to the equation (x+3)^2=2 ?
The solutions to the equation (x+3)^2=2 are x=sqrt(2)-3,x=-sqrt(2)-3
Find the zeros of (x+3)^2=2
The zeros of (x+3)^2=2 are x=sqrt(2)-3,x=-sqrt(2)-3