What are the solutions to the equation x^2+17x+62=2x+6 ?

The solutions to the equation x^2+17x+62=2x+6 are x=-7,x=-8

Find the zeros of x^2+17x+62=2x+6

The zeros of x^2+17x+62=2x+6 are x=-7,x=-8

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x^{2} + 17 x + 62 = 2 x + 6

x = - 7, x = - 8

Solution steps

x^{2} + 17 x + 62 = 2 x + 6

Move

6

to the left side

x^{2} + 17 x + 56 = 2 x

Move

2 x

to the left side

x^{2} + 15 x + 56 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 15 \pm 1 5 ^{2} - 4 \cdot 1 \cdot 56}{2 \cdot 1}

1 5^{2} - 4 \cdot 1 \cdot 56 = 1

x_{1, 2} = \frac{- 15 \pm 1}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 15 + 1}{2 \cdot 1}, x_{2} = \frac{- 15 - 1}{2 \cdot 1}

x = \frac{- 15 + 1}{2 \cdot 1} : - 7

x = \frac{- 15 - 1}{2 \cdot 1} : - 8

The solutions to the quadratic equation are:

x = - 7, x = - 8

x^{2} + (- 2)^{2} = 1

t, s t + 1 = t^{2} + 5

2 x^{2} + 8 x = - 2

x, x^{2} + x = y^{2} + y

x, x^{2} + 2 y^{2} + z^{2} - 4 x + 4 y - 2 z + 3 = 0

What are the solutions to the equation x^2+17x+62=2x+6 ?
The solutions to the equation x^2+17x+62=2x+6 are x=-7,x=-8
Find the zeros of x^2+17x+62=2x+6
The zeros of x^2+17x+62=2x+6 are x=-7,x=-8