What are the solutions to the equation x^2+5x+16=0 ?

The solutions to the equation x^2+5x+16=0 are x=-5/2+i(sqrt(39))/2 ,x=-5/2-i(sqrt(39))/2

Find the zeros of x^2+5x+16=0

The zeros of x^2+5x+16=0 are x=-5/2+i(sqrt(39))/2 ,x=-5/2-i(sqrt(39))/2

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x^{2} + 5 x + 16 = 0

x = - \frac{5}{2} + i \frac{39}{2}, x = - \frac{5}{2} - i \frac{39}{2}

Solution steps

x^{2} + 5 x + 16 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 5 \pm 5 ^{2} - 4 \cdot 1 \cdot 16}{2 \cdot 1}

Simplify

5^{2} - 4 \cdot 1 \cdot 16 : 39 i

x_{1, 2} = \frac{- 5 \pm 39 i}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 5 + 39 i}{2 \cdot 1}, x_{2} = \frac{- 5 - 39 i}{2 \cdot 1}

x = \frac{- 5 + 39 i}{2 \cdot 1} : - \frac{5}{2} + i \frac{39}{2}

x = \frac{- 5 - 39 i}{2 \cdot 1} : - \frac{5}{2} - i \frac{39}{2}

The solutions to the quadratic equation are:

x = - \frac{5}{2} + i \frac{39}{2}, x = - \frac{5}{2} - i \frac{39}{2}

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(6 - x) (2 x - 5) + 30 = 0

- 0.05 x^{2} - 10 x + 480 = 0

5 - 3 x - x^{2} = 3 x^{2} + 4 x + 3

What are the solutions to the equation x^2+5x+16=0 ?
The solutions to the equation x^2+5x+16=0 are x=-5/2+i(sqrt(39))/2 ,x=-5/2-i(sqrt(39))/2
Find the zeros of x^2+5x+16=0
The zeros of x^2+5x+16=0 are x=-5/2+i(sqrt(39))/2 ,x=-5/2-i(sqrt(39))/2