What are the solutions to the equation x^2-11x+97=8x+7 ?

The solutions to the equation x^2-11x+97=8x+7 are x=10,x=9

Find the zeros of x^2-11x+97=8x+7

The zeros of x^2-11x+97=8x+7 are x=10,x=9

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

x^{2} - 11 x + 97 = 8 x + 7

x = 10, x = 9

Solution steps

x^{2} - 11 x + 97 = 8 x + 7

Move

7

to the left side

x^{2} - 11 x + 90 = 8 x

Move

8 x

to the left side

x^{2} - 19 x + 90 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 19 ) \pm ( - 19 ) ^{2} - 4 \cdot 1 \cdot 90}{2 \cdot 1}

(- 19)^{2} - 4 \cdot 1 \cdot 90 = 1

x_{1, 2} = \frac{- ( - 19 ) \pm 1}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 19 ) + 1}{2 \cdot 1}, x_{2} = \frac{- ( - 19 ) - 1}{2 \cdot 1}

x = \frac{- ( - 19 ) + 1}{2 \cdot 1} : 10

x = \frac{- ( - 19 ) - 1}{2 \cdot 1} : 9

The solutions to the quadratic equation are:

x = 10, x = 9

- \frac{165}{2} (x)^{2} + \frac{303}{2} (x - 1)^{2} - \frac{561}{4} = 0

(6 - x) (2 x - 5) + 30 = 0

- 0.05 x^{2} - 10 x + 480 = 0

5 - 3 x - x^{2} = 3 x^{2} + 4 x + 3

2 b^{2} + 11 b + 13 = 0

What are the solutions to the equation x^2-11x+97=8x+7 ?
The solutions to the equation x^2-11x+97=8x+7 are x=10,x=9
Find the zeros of x^2-11x+97=8x+7
The zeros of x^2-11x+97=8x+7 are x=10,x=9