What are the solutions to the equation -0.05x^2-10x+480=0 ?

The solutions to the equation -0.05x^2-10x+480=0 are x=-240,x=40

Find the zeros of -0.05x^2-10x+480=0

The zeros of -0.05x^2-10x+480=0 are x=-240,x=40

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- 0.05 x^{2} - 10 x + 480 = 0

x = - 240, x = 40

Solution steps

- 0.05 x^{2} - 10 x + 480 = 0

Multiply both sides by

100

- 5 x^{2} - 1000 x + 48000 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 1000 ) \pm ( - 1000 ) ^{2} - 4 ( - 5 ) \cdot 48000}{2 ( - 5 )}

(- 1000)^{2} - 4 (- 5) \cdot 48000 = 1400

x_{1, 2} = \frac{- ( - 1000 ) \pm 1400}{2 ( - 5 )}

Separate the solutions

x_{1} = \frac{- ( - 1000 ) + 1400}{2 ( - 5 )}, x_{2} = \frac{- ( - 1000 ) - 1400}{2 ( - 5 )}

x = \frac{- ( - 1000 ) + 1400}{2 ( - 5 )} : - 240

x = \frac{- ( - 1000 ) - 1400}{2 ( - 5 )} : 40

The solutions to the quadratic equation are:

x = - 240, x = 40

5 - 3 x - x^{2} = 3 x^{2} + 4 x + 3

2 b^{2} + 11 b + 13 = 0

a, (a - b)^{2} = 64

x, x^{2} + y^{2} - 4 x - 10 y + 29 = 0

5 n^{2} - 3 n = 2

What are the solutions to the equation -0.05x^2-10x+480=0 ?
The solutions to the equation -0.05x^2-10x+480=0 are x=-240,x=40
Find the zeros of -0.05x^2-10x+480=0
The zeros of -0.05x^2-10x+480=0 are x=-240,x=40