What are the solutions to the equation 4x^2+16x+49=8 ?

The solutions to the equation 4x^2+16x+49=8 are x=-2+i 5/2 ,x=-2-i 5/2

Find the zeros of 4x^2+16x+49=8

The zeros of 4x^2+16x+49=8 are x=-2+i 5/2 ,x=-2-i 5/2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

4 x^{2} + 16 x + 49 = 8

x = - 2 + i \frac{5}{2}, x = - 2 - i \frac{5}{2}

Solution steps

4 x^{2} + 16 x + 49 = 8

Move

8

to the left side

4 x^{2} + 16 x + 41 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 16 \pm 1 6 ^{2} - 4 \cdot 4 \cdot 41}{2 \cdot 4}

Simplify

1 6^{2} - 4 \cdot 4 \cdot 41 : 20 i

x_{1, 2} = \frac{- 16 \pm 20 i}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- 16 + 20 i}{2 \cdot 4}, x_{2} = \frac{- 16 - 20 i}{2 \cdot 4}

x = \frac{- 16 + 20 i}{2 \cdot 4} : - 2 + i \frac{5}{2}

x = \frac{- 16 - 20 i}{2 \cdot 4} : - 2 - i \frac{5}{2}

The solutions to the quadratic equation are:

x = - 2 + i \frac{5}{2}, x = - 2 - i \frac{5}{2}

4 t^{2} - 12 t + 9 = 0

- 8 x^{2} + 13 x + 6 = 0

0 = 4 x^{2} - 72 x

0 = - \frac{1}{4} (x - 4)^{2} + 8

1521 = 13 x^{2}

What are the solutions to the equation 4x^2+16x+49=8 ?
The solutions to the equation 4x^2+16x+49=8 are x=-2+i 5/2 ,x=-2-i 5/2
Find the zeros of 4x^2+16x+49=8
The zeros of 4x^2+16x+49=8 are x=-2+i 5/2 ,x=-2-i 5/2