What are the solutions to the equation 4t^2-12t+9=0 ?

The solutions to the equation 4t^2-12t+9=0 are t= 3/2

Find the zeros of 4t^2-12t+9=0

The zeros of 4t^2-12t+9=0 are t= 3/2

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4 t^{2} - 12 t + 9 = 0

t = \frac{3}{2}

Decimal Notation

t = 1.5

Solution steps

4 t^{2} - 12 t + 9 = 0

Solve with the quadratic formula

t_{1, 2} = \frac{- ( - 12 ) \pm ( - 12 ) ^{2} - 4 \cdot 4 \cdot 9}{2 \cdot 4}

(- 12)^{2} - 4 \cdot 4 \cdot 9 = 0

t_{1, 2} = \frac{- ( - 12 ) \pm 0}{2 \cdot 4}

t = \frac{- ( - 12 )}{2 \cdot 4}

\frac{- ( - 12 )}{2 \cdot 4} = \frac{3}{2}

t = \frac{3}{2}

The solution to the quadratic equation is:

t = \frac{3}{2}

- 8 x^{2} + 13 x + 6 = 0

0 = 4 x^{2} - 72 x

0 = - \frac{1}{4} (x - 4)^{2} + 8

1521 = 13 x^{2}

x^{2} + x (x - 6) = 0

What are the solutions to the equation 4t^2-12t+9=0 ?
The solutions to the equation 4t^2-12t+9=0 are t= 3/2
Find the zeros of 4t^2-12t+9=0
The zeros of 4t^2-12t+9=0 are t= 3/2