What are the solutions to the equation (3w+4)(2w-7)=0 ?

The solutions to the equation (3w+4)(2w-7)=0 are w=-4/3 ,w= 7/2

Find the zeros of (3w+4)(2w-7)=0

The zeros of (3w+4)(2w-7)=0 are w=-4/3 ,w= 7/2

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(3 w + 4) (2 w - 7) = 0

w = - \frac{4}{3}, w = \frac{7}{2}

Decimal Notation

w = - 1.33333 \dots, w = 3.5

Solution steps

(3 w + 4) (2 w - 7) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

3 w + 4 = 0 or 2 w - 7 = 0

Solve

3 w + 4 = 0 : w = - \frac{4}{3}

Solve

2 w - 7 = 0 : w = \frac{7}{2}

The solutions to the quadratic equation are:

w = - \frac{4}{3}, w = \frac{7}{2}

\frac{x ^{2} - 6}{4} = 0

30 x^{2} - 420 x + 1470 = 0

- 3 x^{2} + 7 x = - 2 x - 8

x + 1 = x^{2} - 1

- x^{2} - 2 x - 3 = - 2 x^{2}

What are the solutions to the equation (3w+4)(2w-7)=0 ?
The solutions to the equation (3w+4)(2w-7)=0 are w=-4/3 ,w= 7/2
Find the zeros of (3w+4)(2w-7)=0
The zeros of (3w+4)(2w-7)=0 are w=-4/3 ,w= 7/2