What are the solutions to the equation x^2+(x-3)^2=549 ?

The solutions to the equation x^2+(x-3)^2=549 are x=18,x=-15

Find the zeros of x^2+(x-3)^2=549

The zeros of x^2+(x-3)^2=549 are x=18,x=-15

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x^{2} + (x - 3)^{2} = 549

x = 18, x = - 15

Solution steps

x^{2} + (x - 3)^{2} = 549

Expand

x^{2} + (x - 3)^{2} : 2 x^{2} - 6 x + 9

2 x^{2} - 6 x + 9 = 549

Move

549

to the left side

2 x^{2} - 6 x - 540 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 6 ) \pm ( - 6 ) ^{2} - 4 \cdot 2 ( - 540 )}{2 \cdot 2}

(- 6)^{2} - 4 \cdot 2 (- 540) = 66

x_{1, 2} = \frac{- ( - 6 ) \pm 66}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- ( - 6 ) + 66}{2 \cdot 2}, x_{2} = \frac{- ( - 6 ) - 66}{2 \cdot 2}

x = \frac{- ( - 6 ) + 66}{2 \cdot 2} : 18

x = \frac{- ( - 6 ) - 66}{2 \cdot 2} : - 15

The solutions to the quadratic equation are:

x = 18, x = - 15

m^{2} - 8 m - 20 = 0

3 (a - 5) (a + 2) = 0

y, z = x^{2} y^{2} + x^{3} y

x, f x = x^{2}

(t) = - 0.0002 t^{2} + 0.06 t

What are the solutions to the equation x^2+(x-3)^2=549 ?
The solutions to the equation x^2+(x-3)^2=549 are x=18,x=-15
Find the zeros of x^2+(x-3)^2=549
The zeros of x^2+(x-3)^2=549 are x=18,x=-15