What are the solutions to the equation m^2-8m-20=0 ?

The solutions to the equation m^2-8m-20=0 are m=10,m=-2

Find the zeros of m^2-8m-20=0

The zeros of m^2-8m-20=0 are m=10,m=-2

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m^{2} - 8 m - 20 = 0

m = 10, m = - 2

Solution steps

m^{2} - 8 m - 20 = 0

Solve with the quadratic formula

m_{1, 2} = \frac{- ( - 8 ) \pm ( - 8 ) ^{2} - 4 \cdot 1 \cdot ( - 20 )}{2 \cdot 1}

(- 8)^{2} - 4 \cdot 1 \cdot (- 20) = 12

m_{1, 2} = \frac{- ( - 8 ) \pm 12}{2 \cdot 1}

Separate the solutions

m_{1} = \frac{- ( - 8 ) + 12}{2 \cdot 1}, m_{2} = \frac{- ( - 8 ) - 12}{2 \cdot 1}

m = \frac{- ( - 8 ) + 12}{2 \cdot 1} : 10

m = \frac{- ( - 8 ) - 12}{2 \cdot 1} : - 2

The solutions to the quadratic equation are:

m = 10, m = - 2

3 (a - 5) (a + 2) = 0

y, z = x^{2} y^{2} + x^{3} y

x, f x = x^{2}

(t) = - 0.0002 t^{2} + 0.06 t

36 t^{2} - 12 t + 1 = 0

What are the solutions to the equation m^2-8m-20=0 ?
The solutions to the equation m^2-8m-20=0 are m=10,m=-2
Find the zeros of m^2-8m-20=0
The zeros of m^2-8m-20=0 are m=10,m=-2