What are the solutions to the equation x^2-4x+6=1 ?

The solutions to the equation x^2-4x+6=1 are x=2+i,x=2-i

Find the zeros of x^2-4x+6=1

The zeros of x^2-4x+6=1 are x=2+i,x=2-i

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x^{2} - 4 x + 6 = 1

x = 2 + i, x = 2 - i

Solution steps

x^{2} - 4 x + 6 = 1

Move

1

to the left side

x^{2} - 4 x + 5 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 4 ) \pm ( - 4 ) ^{2} - 4 \cdot 1 \cdot 5}{2 \cdot 1}

Simplify

(- 4)^{2} - 4 \cdot 1 \cdot 5 : 2 i

x_{1, 2} = \frac{- ( - 4 ) \pm 2 i}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 4 ) + 2 i}{2 \cdot 1}, x_{2} = \frac{- ( - 4 ) - 2 i}{2 \cdot 1}

x = \frac{- ( - 4 ) + 2 i}{2 \cdot 1} : 2 + i

x = \frac{- ( - 4 ) - 2 i}{2 \cdot 1} : 2 - i

The solutions to the quadratic equation are:

x = 2 + i, x = 2 - i

x^{2} - 4 x + 4 + x^{2} + 4 x + 4 = 3 x^{2} - x + x - 4

7 x^{2} - 3 x + 10 = 0

9 x^{2} - 42 x + 45 = 0

x^{2} + x - 48 = 0

z^{2} + 5 z - 3 = 0

What are the solutions to the equation x^2-4x+6=1 ?
The solutions to the equation x^2-4x+6=1 are x=2+i,x=2-i
Find the zeros of x^2-4x+6=1
The zeros of x^2-4x+6=1 are x=2+i,x=2-i