What are the solutions to the equation 11^2+10^2=x^2 ?

The solutions to the equation 11^2+10^2=x^2 are x=sqrt(221),x=-sqrt(221)

Find the zeros of 11^2+10^2=x^2

The zeros of 11^2+10^2=x^2 are x=sqrt(221),x=-sqrt(221)

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1 1^{2} + 1 0^{2} = x^{2}

x = 221, x = - 221

Decimal Notation

x = 14.86606 \dots, x = - 14.86606 \dots

Solution steps

1 1^{2} + 1 0^{2} = x^{2}

Switch sides

x^{2} = 1 1^{2} + 1 0^{2}

Simplify

1 1^{2} + 1 0^{2} : 221

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 221, x = - 221

3 (x - 2)^{2} = 12

x \cdot (x - 3) = 0

x^{2} - 5 x - 11 = - 7 x - 3

y^{2} - 2 y + 5

(4 x - 5)^{2} = 49

What are the solutions to the equation 11^2+10^2=x^2 ?
The solutions to the equation 11^2+10^2=x^2 are x=sqrt(221),x=-sqrt(221)
Find the zeros of 11^2+10^2=x^2
The zeros of 11^2+10^2=x^2 are x=sqrt(221),x=-sqrt(221)