What are the solutions to the equation m^2-8m+17=0 ?

The solutions to the equation m^2-8m+17=0 are m=4+i,m=4-i

Find the zeros of m^2-8m+17=0

The zeros of m^2-8m+17=0 are m=4+i,m=4-i

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m^{2} - 8 m + 17 = 0

m = 4 + i, m = 4 - i

Solution steps

m^{2} - 8 m + 17 = 0

Solve with the quadratic formula

m_{1, 2} = \frac{- ( - 8 ) \pm ( - 8 ) ^{2} - 4 \cdot 1 \cdot 17}{2 \cdot 1}

Simplify

(- 8)^{2} - 4 \cdot 1 \cdot 17 : 2 i

m_{1, 2} = \frac{- ( - 8 ) \pm 2 i}{2 \cdot 1}

Separate the solutions

m_{1} = \frac{- ( - 8 ) + 2 i}{2 \cdot 1}, m_{2} = \frac{- ( - 8 ) - 2 i}{2 \cdot 1}

m = \frac{- ( - 8 ) + 2 i}{2 \cdot 1} : 4 + i

m = \frac{- ( - 8 ) - 2 i}{2 \cdot 1} : 4 - i

The solutions to the quadratic equation are:

m = 4 + i, m = 4 - i

525 = - 0.25 q^{2} + 750

4 x - x^{2} = - 3 x + 6

y, m = y^{2} - y \frac{1}{x ^{2}} - x^{1}

r^{2} - 8 r + 15 = 0

1100 - x^{2} = 300 + x^{2}

What are the solutions to the equation m^2-8m+17=0 ?
The solutions to the equation m^2-8m+17=0 are m=4+i,m=4-i
Find the zeros of m^2-8m+17=0
The zeros of m^2-8m+17=0 are m=4+i,m=4-i