What are the solutions to the equation 2x^2=4+x^2 ?

The solutions to the equation 2x^2=4+x^2 are x=2,x=-2

Find the zeros of 2x^2=4+x^2

The zeros of 2x^2=4+x^2 are x=2,x=-2

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2 x^{2} = 4 + x^{2}

x = 2, x = - 2

Solution steps

2 x^{2} = 4 + x^{2}

Move

x^{2}

to the left side

x^{2} = 4

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 4, x = - 4

4 = 2

- 4 = - 2

x = 2, x = - 2

m^{2} - 8 m + 17 = 0

525 = - 0.25 q^{2} + 750

4 x - x^{2} = - 3 x + 6

y, m = y^{2} - y \frac{1}{x ^{2}} - x^{1}

r^{2} - 8 r + 15 = 0

What are the solutions to the equation 2x^2=4+x^2 ?
The solutions to the equation 2x^2=4+x^2 are x=2,x=-2
Find the zeros of 2x^2=4+x^2
The zeros of 2x^2=4+x^2 are x=2,x=-2