What are the solutions to the equation 4x-x^2=-3x+6 ?

The solutions to the equation 4x-x^2=-3x+6 are x=1,x=6

Find the zeros of 4x-x^2=-3x+6

The zeros of 4x-x^2=-3x+6 are x=1,x=6

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4 x - x^{2} = - 3 x + 6

x = 1, x = 6

Solution steps

4 x - x^{2} = - 3 x + 6

Move

6

to the left side

4 x - x^{2} - 6 = - 3 x

Move

3 x

to the left side

- x^{2} + 7 x - 6 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 7 \pm 7 ^{2} - 4 ( - 1 ) ( - 6 )}{2 ( - 1 )}

7^{2} - 4 (- 1) (- 6) = 5

x_{1, 2} = \frac{- 7 \pm 5}{2 ( - 1 )}

Separate the solutions

x_{1} = \frac{- 7 + 5}{2 ( - 1 )}, x_{2} = \frac{- 7 - 5}{2 ( - 1 )}

x = \frac{- 7 + 5}{2 ( - 1 )} : 1

x = \frac{- 7 - 5}{2 ( - 1 )} : 6

The solutions to the quadratic equation are:

x = 1, x = 6

y, m = y^{2} - y \frac{1}{x ^{2}} - x^{1}

r^{2} - 8 r + 15 = 0

1100 - x^{2} = 300 + x^{2}

120 = 5 (t)^{2}

d^{2} + 6 d + 5 = 0

What are the solutions to the equation 4x-x^2=-3x+6 ?
The solutions to the equation 4x-x^2=-3x+6 are x=1,x=6
Find the zeros of 4x-x^2=-3x+6
The zeros of 4x-x^2=-3x+6 are x=1,x=6