What are the solutions to the equation 9x^2+48x=36 ?

The solutions to the equation 9x^2+48x=36 are x= 2/3 ,x=-6

Find the zeros of 9x^2+48x=36

The zeros of 9x^2+48x=36 are x= 2/3 ,x=-6

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9 x^{2} + 48 x = 36

x = \frac{2}{3}, x = - 6

Decimal Notation

x = 0.66666 \dots, x = - 6

Solution steps

9 x^{2} + 48 x = 36

Move

36

to the left side

9 x^{2} + 48 x - 36 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 48 \pm 4 8 ^{2} - 4 \cdot 9 ( - 36 )}{2 \cdot 9}

4 8^{2} - 4 \cdot 9 (- 36) = 60

x_{1, 2} = \frac{- 48 \pm 60}{2 \cdot 9}

Separate the solutions

x_{1} = \frac{- 48 + 60}{2 \cdot 9}, x_{2} = \frac{- 48 - 60}{2 \cdot 9}

x = \frac{- 48 + 60}{2 \cdot 9} : \frac{2}{3}

x = \frac{- 48 - 60}{2 \cdot 9} : - 6

The solutions to the quadratic equation are:

x = \frac{2}{3}, x = - 6

350 + x - 2 x^{2} = 50 + x + x^{2}

x, y^{2} + 2 x y - x^{2} = 0

3 t^{2} - 5 t + 2 = 0

x (x + 3) = 5 x + 3

- 2 x^{2} + 10 x = 12

What are the solutions to the equation 9x^2+48x=36 ?
The solutions to the equation 9x^2+48x=36 are x= 2/3 ,x=-6
Find the zeros of 9x^2+48x=36
The zeros of 9x^2+48x=36 are x= 2/3 ,x=-6