What are the solutions to the equation x(3x+6)=140 ?

The solutions to the equation x(3x+6)=140 are x=(-3+sqrt(429))/3 ,x=-(3+sqrt(429))/3

Find the zeros of x(3x+6)=140

The zeros of x(3x+6)=140 are x=(-3+sqrt(429))/3 ,x=-(3+sqrt(429))/3

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x (3 x + 6) = 140

x = \frac{- 3 + 429}{3}, x = - \frac{3 + 429}{3}

Decimal Notation

x = 5.90410 \dots, x = - 7.90410 \dots

Solution steps

x (3 x + 6) = 140

Expand

x (3 x + 6) : 3 x^{2} + 6 x

3 x^{2} + 6 x = 140

Move

140

to the left side

3 x^{2} + 6 x - 140 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 6 \pm 6 ^{2} - 4 \cdot 3 ( - 140 )}{2 \cdot 3}

6^{2} - 4 \cdot 3 (- 140) = 2429

x_{1, 2} = \frac{- 6 \pm 2 429}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- 6 + 2 429}{2 \cdot 3}, x_{2} = \frac{- 6 - 2 429}{2 \cdot 3}

x = \frac{- 6 + 2 429}{2 \cdot 3} : \frac{- 3 + 429}{3}

x = \frac{- 6 - 2 429}{2 \cdot 3} : - \frac{3 + 429}{3}

The solutions to the quadratic equation are:

x = \frac{- 3 + 429}{3}, x = - \frac{3 + 429}{3}

x, f (x + 1) = (x + 1)^{2} - 4

11 x^{2} - 12 x = 0

6 x^{2} - 3 x - 7 = 0

(x + 8)^{2} + (x - 8)^{2} = x^{2} + 132

- 3 x^{2} + 12 x + 8

What are the solutions to the equation x(3x+6)=140 ?
The solutions to the equation x(3x+6)=140 are x=(-3+sqrt(429))/3 ,x=-(3+sqrt(429))/3
Find the zeros of x(3x+6)=140
The zeros of x(3x+6)=140 are x=(-3+sqrt(429))/3 ,x=-(3+sqrt(429))/3