What are the solutions to the equation 6x^2-3x-7=0 ?

The solutions to the equation 6x^2-3x-7=0 are x=(3+sqrt(177))/(12),x=(3-sqrt(177))/(12)

Find the zeros of 6x^2-3x-7=0

The zeros of 6x^2-3x-7=0 are x=(3+sqrt(177))/(12),x=(3-sqrt(177))/(12)

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6 x^{2} - 3 x - 7 = 0

x = \frac{3 + 177}{12}, x = \frac{3 - 177}{12}

Decimal Notation

x = 1.35867 \dots, x = - 0.85867 \dots

Solution steps

6 x^{2} - 3 x - 7 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 3 ) \pm ( - 3 ) ^{2} - 4 \cdot 6 ( - 7 )}{2 \cdot 6}

(- 3)^{2} - 4 \cdot 6 (- 7) = 177

x_{1, 2} = \frac{- ( - 3 ) \pm 177}{2 \cdot 6}

Separate the solutions

x_{1} = \frac{- ( - 3 ) + 177}{2 \cdot 6}, x_{2} = \frac{- ( - 3 ) - 177}{2 \cdot 6}

x = \frac{- ( - 3 ) + 177}{2 \cdot 6} : \frac{3 + 177}{12}

x = \frac{- ( - 3 ) - 177}{2 \cdot 6} : \frac{3 - 177}{12}

The solutions to the quadratic equation are:

x = \frac{3 + 177}{12}, x = \frac{3 - 177}{12}

(x + 8)^{2} + (x - 8)^{2} = x^{2} + 132

- 3 x^{2} + 12 x + 8

x^{2} + (2 - x)^{2} = 884

x, y^{2} x^{2} - 4 x^{2} = - y^{2} - 9

(2 x - 3)^{2} - (3 x + 1) (3 x - 1) = (x - 7) (x + 2) + 24

What are the solutions to the equation 6x^2-3x-7=0 ?
The solutions to the equation 6x^2-3x-7=0 are x=(3+sqrt(177))/(12),x=(3-sqrt(177))/(12)
Find the zeros of 6x^2-3x-7=0
The zeros of 6x^2-3x-7=0 are x=(3+sqrt(177))/(12),x=(3-sqrt(177))/(12)