What are the solutions to the equation (x+8)^2+(x-8)^2=x^2+132 ?

The solutions to the equation (x+8)^2+(x-8)^2=x^2+132 are x=2,x=-2

Find the zeros of (x+8)^2+(x-8)^2=x^2+132

The zeros of (x+8)^2+(x-8)^2=x^2+132 are x=2,x=-2

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(x + 8)^{2} + (x - 8)^{2} = x^{2} + 132

x = 2, x = - 2

Solution steps

(x + 8)^{2} + (x - 8)^{2} = x^{2} + 132

Expand

(x + 8)^{2} + (x - 8)^{2} : 2 x^{2} + 128

2 x^{2} + 128 = x^{2} + 132

Move

128

to the right side

2 x^{2} = x^{2} + 4

Move

x^{2}

to the left side

x^{2} = 4

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 4, x = - 4

4 = 2

- 4 = - 2

x = 2, x = - 2

- 3 x^{2} + 12 x + 8

x^{2} + (2 - x)^{2} = 884

x, y^{2} x^{2} - 4 x^{2} = - y^{2} - 9

(2 x - 3)^{2} - (3 x + 1) (3 x - 1) = (x - 7) (x + 2) + 24

\frac{1}{2} x^{2} - x - 1 = - x + 1

What are the solutions to the equation (x+8)^2+(x-8)^2=x^2+132 ?
The solutions to the equation (x+8)^2+(x-8)^2=x^2+132 are x=2,x=-2
Find the zeros of (x+8)^2+(x-8)^2=x^2+132
The zeros of (x+8)^2+(x-8)^2=x^2+132 are x=2,x=-2