What are the solutions to the equation 8m^2+20m=12 ?

The solutions to the equation 8m^2+20m=12 are m= 1/2 ,m=-3

Find the zeros of 8m^2+20m=12

The zeros of 8m^2+20m=12 are m= 1/2 ,m=-3

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8 m^{2} + 20 m = 12

m = \frac{1}{2}, m = - 3

Decimal Notation

m = 0.5, m = - 3

Solution steps

8 m^{2} + 20 m = 12

Move

12

to the left side

8 m^{2} + 20 m - 12 = 0

Solve with the quadratic formula

m_{1, 2} = \frac{- 20 \pm 2 0 ^{2} - 4 \cdot 8 ( - 12 )}{2 \cdot 8}

2 0^{2} - 4 \cdot 8 (- 12) = 28

m_{1, 2} = \frac{- 20 \pm 28}{2 \cdot 8}

Separate the solutions

m_{1} = \frac{- 20 + 28}{2 \cdot 8}, m_{2} = \frac{- 20 - 28}{2 \cdot 8}

m = \frac{- 20 + 28}{2 \cdot 8} : \frac{1}{2}

m = \frac{- 20 - 28}{2 \cdot 8} : - 3

The solutions to the quadratic equation are:

m = \frac{1}{2}, m = - 3

(2 x - 3)^{2} - 8 = 0

a^{2} - 4 a - 32 = 0

(4 x - 3)^{2} - (x - 1) (x - 9) = 0

x^{2} + 10 x + 28

3 z^{2} - 8 z + 4 = 5 z

What are the solutions to the equation 8m^2+20m=12 ?
The solutions to the equation 8m^2+20m=12 are m= 1/2 ,m=-3
Find the zeros of 8m^2+20m=12
The zeros of 8m^2+20m=12 are m= 1/2 ,m=-3