What are the solutions to the equation 5x^2+9x-6=10x ?

The solutions to the equation 5x^2+9x-6=10x are x= 6/5 ,x=-1

Find the zeros of 5x^2+9x-6=10x

The zeros of 5x^2+9x-6=10x are x= 6/5 ,x=-1

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5 x^{2} + 9 x - 6 = 10 x

x = \frac{6}{5}, x = - 1

Decimal Notation

x = 1.2, x = - 1

Solution steps

5 x^{2} + 9 x - 6 = 10 x

Move

10 x

to the left side

5 x^{2} - x - 6 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 1 ) \pm ( - 1 ) ^{2} - 4 \cdot 5 ( - 6 )}{2 \cdot 5}

(- 1)^{2} - 4 \cdot 5 (- 6) = 11

x_{1, 2} = \frac{- ( - 1 ) \pm 11}{2 \cdot 5}

Separate the solutions

x_{1} = \frac{- ( - 1 ) + 11}{2 \cdot 5}, x_{2} = \frac{- ( - 1 ) - 11}{2 \cdot 5}

x = \frac{- ( - 1 ) + 11}{2 \cdot 5} : \frac{6}{5}

x = \frac{- ( - 1 ) - 11}{2 \cdot 5} : - 1

The solutions to the quadratic equation are:

x = \frac{6}{5}, x = - 1

x, x^{2} - 49 = 0

8 x^{2} + 2 x = 7 x

(x - 6) (x - 3) = 4

(6 - x)^{2} - 1 = 0

x, x^{2} + 2 x y = 0

What are the solutions to the equation 5x^2+9x-6=10x ?
The solutions to the equation 5x^2+9x-6=10x are x= 6/5 ,x=-1
Find the zeros of 5x^2+9x-6=10x
The zeros of 5x^2+9x-6=10x are x= 6/5 ,x=-1